Neato
1 point
x = foo(y:=bar(), baz(), y) or z should work assuming foo bar and baz are functions being called?
if this is setting y to the effect of bar() + running baz after, then:
x = [bar(), baz()][0] or z
might work
and if you need y to be defined for later use:
x = [(y:=bar()), baz()][0] or z
but thats from memory, not sure if that will even run as written.
if I get to a real computer I'll try that with an actual if statement instead of a bastardized ternary.2 points
foo isn’t a function, it’s a bool. But in any case, as you can see the answer is “with terrible hacks”. Python is not a functional language. It is imperative.
0 points
