Did you guys find this hard? There are only four possible ways to move a ring, two of which are disallowed by the rules. Out of the remaining two, one of them is simply undoing what you just did.
Before studying CS, I recognized it as ‘the bioware puzzle’. They were probably copying their own scribbles fron back then.
Haskell was the hardest, but it looked the most beautiful.
Haskell was the hardest, but it looked the most beautiful.
That pretty much sums that language up
Strange. I find the language hideous, most likely because it resembles math, or maybe because I’m already used to the C-like syntax.
In order to write a haskell program, you must first write the corresponding haskell program.
Functional programming flips your brain around backwards, but shader programming will turn it inside-out.
hanoi :: Integer -> a -> a -> a -> [(a, a)]
hanoi 0 _ _ _ = []
hanoi n a b c = hanoi (n-1) a c b ++ [(a, b)] ++ hanoi (n-1) c b a
From here: https://www.rosettacode.org/wiki/Towers_of_Hanoi#Haskell
Edit: I understand it now. That first line is just a really weird way to define a function.
Welp, imma try myself at an explanation. Mostly cause I haven’t written Haskell in a while either.
So, that first line:
hanoi :: Integer -> a -> a -> a -> [(a, a)]
…actually only declares the function’s type.
In this case, it’s a function that takes an Integer and three values of a generic type a and then returns a list of tuples of those same as.
So, those as are just any types representing the towers. Could be strings, integers, custom data types, whatever. The returned tuples represent movements between towers.
Following that are actually two definitions of the function.
The first definition:
hanoi 0 _ _ _ = []
…is the recursion base case. Function definitions are applied, whenever they match, being evaluated top-to-bottom.
This line specifies that it only matches, if that first Integer is 0. It does not care what the remaining parameters are, so matches them with a wildcard _.
Well, and to the right side of the equals sign, you’ve got the return value for the base case, an empty list.
Then comes the more interesting line, the recursion step:
hanoi n a b c = hanoi (n-1) a c b ++ [(a, b)] ++ hanoi (n-1) c b a
This line matches for any remaining case. Those small letter names are again wildcards, but the matched value is placed into a variable with the provided name.
And then, well, it recursively calls itself, and those ++ are list concations. This line’s only real complexity is the usual Tower Of Hanoi algorithm.
Example for stack
Oh but we don’t play it, we put lighting into rocks and trick them into doing it.
oh, i solved that assignment in school… by finding the algorithm online
As it should be, there’s way too much reengineering of the wheel. Let the big brains of the past do the heavy lifting
Pfft, writing a program that collects user input and displays it is just trite. I’m going to skip straight to building an MMO.
I had enough colleagues unable to type exactly what they asked me into whatever search engine they preferred to accept your statement. If you don’t know how to use a search engine go ask for another job.
“Hey pancake, how do I run all tests via gradle?”
Open your browser, head to Google and type “run all tests in gradle”
“Oh, nice. Thank you for your help!”
And the next day the game starts all over again.
